Erik’s disabled sailboat is floating at a stationary location 3 miles East and 2 miles North of Kingston. A ferry leaves Kingston heading due East toward Edmonds at 12 mph. At the same time, Erik leaves the sailboat in a dinghy heading due South at 10 ft/sec (hoping to intercept the ferry). Edmonds is 6 miles due East of Kingston. After 10 minutes, a Coast Guard boat leaves Kingston heading due East at a speed of 25 ft/sec. Will the Coast Guard boat catch the ferry before it reaches Edmonds? Explain. Simple: if a boat is going 25 ft per sec and ferry is going 1056 feet per sec with a 10 minute head start, will the boat meet the ferry?
First things first Have you tried drawing it? Drawing could really help you visualize directions and location
that was part d. We have a picture but its not needed. I need to figure out the equation best used to calculate
They give you a rate at ft/sec The reference tells you mi/hr You want to convert the coast guards speed from ft/sec to mi/hr
im taking the L for this one
Are you allowed to use a simple calculator? This isn't very hard. It's just a lot explained. Visualizing really helps. That's why I mentioned a drawing/figure
`If a boat is going 25 ft per sec and ferry is going 1056 feet per sec with a 10 minute head start, will the boat meet the ferry?` Which is faster 25ft/sec or 1025ft/sec
wait i think i did my conversion wrongned;uuhawhj
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