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Mathematics 9 Online
BeccaI:

Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share? A right triangle is shown with one leg measuring 4 and another leg measuring 3. The angle across from the leg measuring 3 is marked x degrees, and the angle across from the leg measuring 4 is marked y degrees.

jhonyy9:

please post this image

BeccaI:

1 attachment
jhonyy9:

can you calcule the length of hypotenuse ?

jhonyy9:

do you know the law of sin and the law of cos ?

BeccaI:

I do know the laws, I do not know how to calculate the length of hypotenuse

jhonyy9:

so this is a right triangle and you know the length of legs

BeccaI:

yes the base is 3 and the height is 4

jhonyy9:

and how you calcule the length of hypotenuse ?

jhonyy9:

have you heard about pythagorian numbers ?

BeccaI:

sin ∠ = opposite hypotenuse ???

BeccaI:

opposite/hypotenuse

BeccaI:

or multiply the shortest leg by 2?

jhonyy9:

you have learn about pitagora theorem ?

BeccaI:

i have not

jhonyy9:

the law of sin and the law of cos ?

BeccaI:

i know about that

jhonyy9:

ok sin x and cos y you need get sin x = ? cos y = ?

BeccaI:

The sine of the angle = the length of the opposite side. the length of the hypotenuse.

jhonyy9:

or do you learn about tg and ctg ?

BeccaI:

don't i need the hypotenuse to find sin?

BeccaI:

no we learn sin, tan, and cos

jhonyy9:

why not above you ve wrote thet sin = op/hyp

jhonyy9:

ok but tan = ?

BeccaI:

im reall confused

BeccaI:

we don't need tan

jhonyy9:

yes but how can you writing tan in function of sin and cos ?

BeccaI:

tan ∠ = opposite/adjacent

jhonyy9:

yes this is true but you dont learned about how can you writing the tan using sin and cos ?

BeccaI:

i dont believe so

BeccaI:

i need help with the whole question

jhonyy9:

ok but for you can calcule the length of hypothenuse you need to know the pythagora theorem and sin x with cos y you can calcule just then you know the length of hypothenuse or there is again way but you ve said that you dont learned again about tan and cot

BeccaI:

Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share? This is all I need. I know that the relationship between sin and cos is always equal but I don't know the value of sin x or cos y

jhonyy9:

ok not the hypotenuse with and h so using this how you get the value of sin x and the value of cos y ?

jhonyy9:

with an h

BeccaI:

i dont know

jhonyy9:

above you ve wrote there sin x = ?

BeccaI:

cos y

jhonyy9:

no you ve wrote above that sin x = op / hyp

BeccaI:

oh yes

jhonyy9:

and than you not the hyp by an h and you know that the op equal 3 so how will get the sin x ?

BeccaI:

3/4?

jhonyy9:

why 4 ? the hyp not equal 4

jhonyy9:

the hyp you dont know just note it by an h

BeccaI:

3/h

jhonyy9:

so sin x = 3/h in this way how you write the cos y = ?

BeccaI:

4/h

jhonyy9:

cos y = 4/h and what relation you need getting ?

BeccaI:

that they are equal

jhonyy9:

no what is the question ?

BeccaI:

What relationship do the ratios of sin x° and cos y° share?

jhonyy9:

so what mean this ?

jhonyy9:

how you write the ratios of sin and cos

BeccaI:

im not sure

jhonyy9:

try it

BeccaI:

3:4

jhonyy9:

and how you ve got it ?

BeccaI:

cuz sin is 3 and cos is 4

jhonyy9:

no sin is 3/h and cos is 4/h

jhonyy9:

and in this way (sin x )/cos y) = (3/h)/(4/h) = ?

BeccaI:

do you multiply it?

jhonyy9:

(3/h) divide sign of / (4/h)

BeccaI:

so divide 3/h over 4/h?

jhonyy9:

yes

jhonyy9:

how you divide two fractions ?

BeccaI:

The first step to dividing fractions is to find the reciprocal of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.

BeccaI:

3/h divided by h/4 ??

jhonyy9:

yes multiplie the first by reciprocal of second so in our case how will be ?

jhonyy9:

not divided by reciprocal

BeccaI:

3/h multiplied by h/4

jhonyy9:

exactly and now then you see what can you make with h from numerator and with h from denominator ?

BeccaI:

what is it?

jhonyy9:

|dw:1601074056218:dw|

BeccaI:

0.75

jhonyy9:

have you heard about simplification ?

BeccaI:

is it 0.75

jhonyy9:

no bc. you need getting the relation value of sin and cos

jhonyy9:

how you ve got this value ?

jhonyy9:

you need getting the ratios what is a fraction

BeccaI:

3h/h4

jhonyy9:

i ve said above that there is multiplication not divide

BeccaI:

but that is simplified

jhonyy9:

and not 3h or 4h

jhonyy9:

there is 3/h and 4/h

jhonyy9:

what can you simplifie from there ? - look on this image what i ve posted above

BeccaI:

can we cross simplify to cancel out the h's?

BeccaI:

or 20h

jhonyy9:

exactly and so what will get for ratios ?

BeccaI:

20:h

jhonyy9:

h's are canceled

BeccaI:

20:0

jhonyy9:

how get this 20 ?

BeccaI:

I meant 12

jhonyy9:

no (3/h) * (h/4) = ?

BeccaI:

if we cross simplify 3 multiplied by 4 is 12

jhonyy9:

no you cross just simplifie the h's

BeccaI:

well then im not sure

jhonyy9:

ok how you think it canceled h's what remain there ?

BeccaI:

3/4

jhonyy9:

perfectly so the ratios of sin x and cos y how much will be ?

BeccaI:

3:4

jhonyy9:

yes but correct wrote is 3/4 and write it in tis way (sin x)/(cos y) = 3/4

BeccaI:

thank you so much :)))

jhonyy9:

np was my pleasure and hope so much that you understand it now sure

BeccaI:

i do!

jhonyy9:

ok bye bye

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