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Given the function h(x)=-x^2+10x+32h(x)=−x 2 +10x+32, determine the average rate of change of the function over the interval 3\le x \le 113≤x≤11.
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Welcome to QC (: There's an easy way to do this but not sure if you've learned derivatives, have you?
Stop being formal
I haven't
Fudge Okay then just substitute 3 and 11 in for x \(h(x)=-(3)^2+10(3)+32\) and \(h(x)=-(11)^2+10(11)+32\)
o.0
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Do you know how to solve it? \(-(3)^2+10(3)+32\) \(-(11)^2+10(11)+32\)
56
120
7/15?
Basically like last time (: \(\dfrac{120-56}{11-3}\)
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Ocho
Si
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