Question

Phosphorus-32 has a half-life of 14.0 days. Starting with 2.00 g of 32P, how many grams will remain after 98.0 days ? Express your answer numerically in grams.

Answer 1

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Answer 2

applying the half-life equation to this problem:
your A0 = initial value = 2.00g
t = time = 98.0 days
h = half-life 14.0 days
A = final amount = what you're solving for

plug in the appropriat values into the equation and solve for A