You randomly draw two cards from a well-shuffled standard deck of 52 cards. You replace the first card. What is the probability that you drew a king or a club? Explain your steps or attach a screenshot of your work.
Im gonna be honest, im trash at these kinda things.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mangaartist Im gonna be honest, im trash at these kinda things. \(\color{#0cbb34}{\text{End of Quote}}\) lol sameeeee! Lol I totally understand, It's fine. lol
kk cool
ok, so there are 4 kings and 13 clubs which means one king is a club so your cards to draw are 16 cards that are either clubs or kings
so divide 16 by 52
thatll give you the probability of the first card being it
oh! So is that all there is to the problem? I was kinda nervous, I thought there was a lot more to it than that. lol
hold on
kk
so now you pull a card and there are 51 cards with 15-16 clubs/kings
@dude
i tried to hard, my brain hurts and i cant think
lol okay. Thanks!
@Shadow
Google, how many clubs in a deck then how many kings in a deck. Let add them both, and then you have the probability of getting a club or a king. There are 52 cards in a deck, and x probability of getting a club or king. After the first try, the card is replaced, so there are 52 cards for both tries. Do x/52 times x/52 to get the probability of getting a club or king within two tries.
16/52 * 16/52?
Says there are 13 clubs in a deck and 4 kings.
Oh I realize what you did, good. I don't play cards so I'm just thinking of this too literally. But yes, one of the kings will be a club so you can excommunicate that guy and keep it at 16.
Great! Thank youuuuuuuuu!
You're welcome
i am stuped
so i dont no
lol
I got 9.47% do you think that's right? @Shadow @Aqual
idk
lol kk
Looks right to me
Okay! Thanks!
Join our real-time social learning platform and learn together with your friends!