Question

the equation for a projectiles height versus time is h(t)=-16(t)^2+Vt +h. A tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an initial speed of 110 feet per second. After how many seconds does the ball attain its max height

Answer 1

h(t) = -16t^2 + Vt + h
Velocity at time t is the derivative of the above:
dh/dt = -32t + V
= -32t + 110
This = zero at maximum height so
t = -110/-32
= 3.44 seconds to nearest hundredth.