Given the general identity tan X = sin X/ cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?
do u have a pic?
Ye need a pic or url of the angles
A. tan A= sin A/ Sin C B. cos A= tan (90- A)/ sin (90-C) C. sin C= cos A/ tan C D. cos A= tan C E. sin C= cos (90-C)/ tan A
sorry theirs the screenshot
its ok, i do edmentum to lol
Ok so tan A = sin A / sin C
and sin C = sin A / tan A = sin A / (sin A / cos A) =
what would it equal?
I'm pretty sure it's either B or E
but what do u think the answer would be?
btw this is just the second step to finding the answer
E
why do u think its E?
E is incorrect
i'm confused
ok so sin C = sin A/tan A = sin A/(sin A / cos A) = cos A sin C =? (btw A/tan is a fraction)
ok
new answer?
yea I think I got it now
so what would your final answer be?
I dont think its B now. Im starting to lean on towards C.
inncorrect
Ok lets break it down again
so its B?
Your last two options are A and B so give a explination on why u think B or A is correct
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