Question

A table contains the ordered pairs (3, 42.25) and (5, 50.75). If the relationship in the table is linear, explain how to find the initial value.

Answer 1

sorry no one got to you sooner :/
here's something to hopefully help you:
so we have (3, 42.25) and (5, 50.75)
The linear relationship ( the linear equation ):
y = m x + b ( the slope-intercept form )
if m is the slope, we need to do \[\frac{ y2-y1 }{ x2-x1 }\]
m = ( 50.75 - 42.25 ) / ( 5 - 3 ) = 8.50 / 2 = 4.25
the slope is 4.25.
now, using the first point fill in your y,m,and x:
42.25 = 4.25 * 3 + b
42.25=12.75+b
then, :
b = 42.25 - 12.75
b = 29.50
y = 4.25 * x + 29.50
Answer:
The initial value is : ( 0, 29.50 ) or 29.50.