The sum of two numbers is 48. If one third of one number is 5 greater than one sixth of another number, which of the following is the smaller number?
The way I think you would represent this is that let x and y be the two numbers. \[x + y = 48\] \[\frac{ 1 }{ 3 }x = \frac{ 1 }{ 6 }y + 5\]
Then it's just a system of equations and you solve
how would you solve it if there are no like terms?
Isolate one variable in on equation to where it's like x = blah blah blah, then input it into the other equation then solve for y.
Then you input what you get for y back into the first equation, solving for x. Then you just take whichever of the numbers is smaller.
To answer, " which of the following is the smaller number?"
I got 26
k now solve for the other number. Input it back into the first equation
22 right?
Yes
ok thank you so much
You're welcome
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