The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

The diameter at the center of the tower is

meters. The center of the tower is

meters above the ground.

Question

The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

The diameter at the center of the tower is

meters. The center of the tower is

meters above the ground.

allizy · Answer

attachment

lilianamendez2 · Answer

$\color{#0cbb34}{\text{Originally Posted by}}$ @allizy

$\color{#0cbb34}{\text{End of Quote}}$
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