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KeigoTakami:

here we have a new post owo Solve x2 = −169. (4 points) A-undefined B-13 C-±13 D-−13

boobear3361752:

B

KeigoTakami:

here here

boobear3361752:

lol

KeigoTakami:

so it positive

kayla233:

UH

KeigoTakami:

UH INDEED

kayla233:

idk bro :'(

dude:

@Soupear3361752 Careful, you are doing the root of a negative number

dude:

Rip

KeigoTakami:

im just drinking tea and trying-

boobear3361752:

no, 169 is negative so the square root would be neagtive

kayla233:

I want tea-

KeigoTakami:

mm

boobear3361752:

haha

KeigoTakami:

here

dude:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Wizardear3361752 no, 169 is negative so the square root would be neagtive \(\color{#0cbb34}{\text{End of Quote}}\) Negative roots do not work like that

kayla233:

hold on imma make tea

KeigoTakami:

*gives virtual tea*

mxddi3:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude \(\color{#0cbb34}{\text{Originally Posted by}}\) @Wizardear3361752 no, 169 is negative so the square root would be neagtive \(\color{#0cbb34}{\text{End of Quote}}\) Negative roots do not work like that \(\color{#0cbb34}{\text{End of Quote}}\) would it be the +/- sqrt of -13?

dude:

You'd get an imaginary number Based on the assumption that you haven't dealt with those it would be neither

kayla233:

HOLD UP I THINK I KNOW

KeigoTakami:

i have my mind set on ±13 because i keep getting it wrong on others ant thats the one it is

boobear3361752:

although i jus remembered that a negative times a nagative gets a positive but a negative times a positive gets a negative sooooo

kayla233:

gimme a sec :-)

KeigoTakami:

:D

dude:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Sandwichear3361752 although i jus remembered that a negative times a nagative gets a positive but a negative times a positive gets a negative sooooo \(\color{#0cbb34}{\text{End of Quote}}\) True, but can you multiply two of the exact same numbers to get a negative?

KeigoTakami:

mm-

boobear3361752:

depends on if they r positive or not

dude:

Are you sure?

boobear3361752:

u cant multiply two negatives and get a negative

boobear3361752:

yes

mxddi3:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude You'd get an imaginary number Based on the assumption that you haven't dealt with those it would be neither \(\color{#0cbb34}{\text{End of Quote}}\) so no "real numbers" ?

kayla233:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KeigoTakami i have my mind set on ±13 because i keep getting it wrong on others ant thats the one it is \(\color{#0cbb34}{\text{End of Quote}}\) if you got the others wrong then it has to be +13 right?

boobear3361752:

real numbers would work if thats an aswer

KeigoTakami:

All numbers are in your head-

KeigoTakami:

GASP

kayla233:

BRUH

boobear3361752:

yo i jus got this from the website.... You have been warned: It is better to guide the user to an answer rather than doing all the work yourself. We discourage giving out answers without letting the asker at least take some part in the analysis - the aim of this site is to teach. Please refer to our Rules at https://questioncove.com/rules for more information. Thank you.

dude:

What is -7 \(\times\) -7 and 7 \(\times\) 7 Would they yield you a negative?

KeigoTakami:

no-

mxddi3:

they're both 49, no negative

boobear3361752:

-7x-7=49

dude:

Precisely (:

boobear3361752:

correct both r +

dude:

Right but remember roots are the same exact one

KeigoTakami:

owo yey

dude:

\(7^2\) or \(-7^2\) will not give you a negative

KeigoTakami:

yeh u right

mxddi3:

so the answer is undefined? because the answer is imaginary numbers @dude ?

dude:

Yeah

boobear3361752:

yuh

mxddi3:

so undefined means imaginary numbers?

dude:

imaginary numbers are not really numbers

KeigoTakami:

help me again- i have a new question-

boobear3361752:

alr

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