Question

a ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/seconds squared. what is the final velocity after 6.0 seconds

Answer 1

vf = vi + at

where vi = initial velocity (it starts from rest, so vi = 0)
vf = final velocity (which you'll solve for)
a = acceleration (given as a = 3.2 m/s/s)
and t is time (given as 6.0 seconds)

plug in and solve for vf