Question

What is the perimeter of a polygon with vertices at (-3, 1), (5, 1), (-3, 4), (5, 4

Answer 1

try making a drawing, and then it will be easier to find the perimeter, you can graph and it would help

Answer 2

where ya at now?

Answer 3

im graphing

Answer 4

alright, keep working on it.

Answer 5

i got 16.54 but i think its wrong

Answer 6

How about you just take the distance from each point to the next and add them up? see what u get

Answer 7

Yeah you shouldn't get a decimal

Answer 8

Thats what i did i used the distance formula to find the distance between the points and thats where i think i got something wrong, here let me show you my work

Answer 9

Do you have a photo of any sort?

Answer 10

AB=√(5--3)^2-(1-1)^2=√64=8
BC=√(-3-5)^2-(4-1)^2=√-73=8.54
cd would be the same as AD and ad would be the same as BC

Then i added 8.54 and 8 and got 16.54

Answer 11

i mean CD would be the same as AB

Answer 12

I got 21 but I might not be doing this with the same formula you are.

Answer 13

The distance formula
√(x2-x1)^2-(y2-y1)^2

Answer 14

I dont know what im doing wrong

Answer 15

you don't need a distance formula. This is a lot simpler of a problem than you think.
If you look at the following coordinates, some match with their x-values and some- with y values. (-3, 1), (5, 1), (-3, 4), (5, 4
The distance between (-3,1) and (5,1) is 8. And the distance between (-3, 1 and -3,4) is 3.
These are 2 sides of our rectangle. now use 2(length) + 2(width) = perimeter to solve for the perimeter

Answer 16

oh so it would be 22

Answer 17

yes.

Answer 18

thank you, your way helps

Answer 19

np.