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CalandraWadley1212:

A 46 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1368.

Hoodmemes:

Whats the question?

CalandraWadley1212:

A 46 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1368.

Hoodmemes:

Is that the question is it a is this true or false and why is it false or true question?

CalandraWadley1212:

A 46 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1368.Find the substance's half-life, in days.Round your answer to the nearest tenth.

Hoodmemes:

Is there more information included?

CalandraWadley1212:

A 46 gram sample of a substance by-product of fireworks has a k-value of 0.1368. N = Noekt No = initial mass (at time t = 0) N = mass at timet k= a positive constant that depends on the substance itself and on the units used to measure time t = time, in days

Hoodmemes:

Ok, first ya wanna do N(t) = (Nø)  •  e^[- k • t ]

Hoodmemes:

Then 23 = (½)  •  (46) half life tho

CalandraWadley1212:

How you put it in the calculator

Hoodmemes:

no im solving it for u

CalandraWadley1212:

Ok thanks

Hoodmemes:

well just doing the equation part

CalandraWadley1212:

Ok

Hoodmemes:

23 = (46)  •  e^[- (0.137) • t ] divide by 46

CalandraWadley1212:

Ok thanks you

Hoodmemes:

Then u would wanna do 0.5 = e^[- (0.137) • t ] take the natural log of both sides

Hoodmemes:

  ln[0.5] = - (0.137) • t 

CalandraWadley1212:

Oh

Hoodmemes:

t = 5.06 days round this to the nearest ten

Hoodmemes:

have u rounded it yet?

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