Question

Solve this system of linear equations. Separate the x- and y-values with a comma.

Answer 1

so do you know your steps to figure out the answer?

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @payton
so do you know your steps to figure out the answer?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes

Answer 3

i think

Answer 4

okay so then you should be able to explain your first step...which is....

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @payton
okay so then you should be able to explain your first step...which is....
\(\color{#0cbb34}{\text{End of Quote}}\)
multiply the top by -1?

Answer 6

how you need to solve this system by what method using ?

by elimination method or by substitution method ?

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
how you need to solve this system by what method using ?

by elimination method or by substitution method ?
\(\color{#0cbb34}{\text{End of Quote}}\)
either one

Answer 8

so than you check this system the easyst is the elimination method

do you know it ?

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
so than you check this system the easyst is the elimination method

do you know it ?
\(\color{#0cbb34}{\text{End of Quote}}\)
i think so

Answer 10

ok what you need to do like a first step ?

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
ok what you need to do like a first step ?
\(\color{#0cbb34}{\text{End of Quote}}\)
do i multiply the top equation by -1?

Answer 12

yes but i say multiplie the bottom bc. to eliminate the minus from the left part

the result will be the same

Answer 13

in my head, i would think so...

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
yes but i say multiplie the bottom bc. to eliminate the minus from the left part

the result will be the same
\(\color{#0cbb34}{\text{End of Quote}}\)
oh ok lemme do that real quick

Answer 15

do you wan write your calcule here- i like check it

Answer 16

is it that?^

Answer 17

2x = 56 -20y
-16x = 92-20y *(-1)

what you get ?

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
2x = 56 -20y
-16x = 92-20y *(-1)

what you get ?
\(\color{#0cbb34}{\text{End of Quote}}\)
thats the original problem, then i multiplied the bottom by -1 and got
16x=-92+20y

then it would be

2x=56-20y +
16x=-92+20y

am i wrong?

Answer 19

no

and now ?

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
no

and now ?
\(\color{#0cbb34}{\text{End of Quote}}\)
ok then i add them together

Answer 21

yes term by term

Answer 22

hello

Answer 23

is that right?

Answer 24

yes and x= ?

Answer 25

-2?

Answer 26

yes

Answer 27

and now y = ?

Answer 28

so next don't u plug in -2 for x?

Answer 29

yes

Answer 30

does it matter which equation?

Answer 31

no indifferent

Answer 32

i'll do it for the top one

Answer 33

ok

Answer 34

didn't mean to delete it

Answer 35

this is easy you can make the calcule in your head

Answer 36

just substitute the -2 in place of x and calcule the value of y

Answer 37

so would it just be -4=56-20y?

Answer 38

yes and y = ?

Answer 39

idk if thats right

Answer 40

no

in the front of 20y where is the minus ?

Answer 41

oh so it would be -20y?

Answer 42

yes

and y = ?

Answer 43

-60 = -20y

???

Answer 44

3?

Answer 45

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
-60 = -20y

???
\(\color{#0cbb34}{\text{End of Quote}}\)
Dont u divide???

Answer 46

just divide both sides by -20

Answer 47

3

Answer 48

\(\color{#0cbb34}{\text{Originally Posted by}}\) @olivia14
3
\(\color{#0cbb34}{\text{End of Quote}}\)
Yur

Answer 49

exactly

Answer 50

Seee ur smart babygirlll

Answer 51

ok so it would be -2,3?

Answer 52

\(\color{#0cbb34}{\text{Originally Posted by}}\) @olivia14
ok so it would be -2,3?
\(\color{#0cbb34}{\text{End of Quote}}\)
Yuh

Answer 53

yes

Answer 54

thank u @jhonyy9

Answer 55

anytime with my pleasure just tag me and i will try help you than i m here online

bye bye

Answer 56

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
anytime with my pleasure just tag me and i will try help you than i m here online

bye bye
\(\color{#0cbb34}{\text{End of Quote}}\)
ok thank u again!

Answer 57

yw