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Mathematics 25 Online
deathsindragon:

se desmos to sketch the behavior f(x)=x^5-3x^3+3 what is the degree? is the degree an even or an odd? what is the leading coefficient? is the leading coefficient as a positive or negative? describe the end behavior? evaluate the given function when x=2? what is the constant term?

deathsindragon:

meant use desmos

darkknight:

Can you not post random stuff... @deathsindragon wants his question answered

darkknight:

Okay so the degree is just the highest exponent in your function of that variable, so 5 The degree is an odd number. The leading coefficient is the number written in front of the variable that contains the degree, so in this case 1, because x^5 is 1x^5 The leading coefficient is clearly positive, bcuz 1 is a positive number The End behaviors basically means the limits, so how the functions look as x approaches infinity and negative infinity. So we can see that as x approaches negative infinity, y values approach negative infinity, and as x values approach positive infinity, y values approach positive infinity Plug x into the function and solve for y,

darkknight:

And lastly, the constant term is the value that can't change because it is not multiplied or divided by a variable, so in this case the constant term is 3.

deathsindragon:

explain end behavior better plz, i stupid

darkknight:

end behavior is how the graph looks like as x values get bigger and bigger to both the left and the right. So basically when we graphed this as we go further and further to the left (for x-values) we can see the y-values going super far down right? So we can say the end behavior as x approaches negative infinity (larger negative x-values) is negative infinity

darkknight:

As x approaches infinity (larger and larger POSITIVE x-values) we can see that the y-values are approaching infinity, because they are getting bigger and bigger. So we can say that the end behavior as x approaches infinity is infinity

deathsindragon:

mk and evaluate it with x=2 can u explain that easier

darkknight:

Yeah, you have your function x^{5}-3x^{3}+3, just plug in 2 for x and see what y value you get

darkknight:

Good with everything?

deathsindragon:

mk, thx

darkknight:

np

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