The law of costumes is a^2 + b^2abcosC=^2. Find the value of 2abcosC.
law of costumes?
I think you meant cosines, I'll get to you.
Yes I meant cosines lol
The law of costumes is c^2=a2+b2﹣2abcos(C) Find the value of 2abcosC. To do this a we need to solve for 2abcos(C) Basically we add 2abcos(C) to both sides, Do you have an idea of what to do from there?
I already answered it but thanks, honestly I didn't think anyone was gonna respond
Like we need to find what 2abcos(C) is, if we add -2abcos(C) to both sides it will be positive (2abcos(C)) on the left side (which is what we are trying to solve for) and get canceled on the right side.
Oh, its all good. Have a good day, also be sure to click best response but you don't have to. :)
Thank you for trying to help me. You have a good day as well
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