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Mathematics 8 Online
Kenia:

The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a parallelogram. Parallelogram GRPC with point B between C and P forming triangle GCB where GC equals 400 ft, CB equals 350 ft, and GB equals 450 ft, point E is outside parallelogram and segments BE and PE form triangle BPE where BP equals 250 ft. Part A: Identify a pair of similar triangles. (2 points) Part B: Explain how you know the triangles from Part A are similar. (4 points) Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

sealake101:

so what all do u know abt triangles and Parallelograms?

Kenia:

only a bit but I wouldn't mind a review

sealake101:

ok so...

sealake101:

parallelograms opposite sides are congruent. Knowing this you can label the opposite lengths of the parallelogram

jhonyy9:

part A. ??? @sealake101

sealake101:

i was just saying she said she could use a review on triangles and Parallelograms

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 about alternate interior - exterior congruently angles - did you ve heard ? \(\color{#0cbb34}{\text{End of Quote}}\)

jhonyy9:

and how are these opposite angles in point B ?

jhonyy9:

@sealake101 please continue i m here just to help you

sealake101:

ok so what exactly r u unsure of

sealake101:

so for part A you need to find a pair of triangles that r similar

Kenia:

yea that's what im trying

Kenia:

did u see the diagram

sealake101:

so there are only 2 triangles in the diagram right

sealake101:

whaich are BPE and GCB

sealake101:

so what would that tell u for part A?

Kenia:

oh I thought it was 3

sealake101:

ok so part B...

sealake101:

now that part A is answered who are they similar?

sealake101:

how*

jhonyy9:

good job @sealake101 so in this way step by step please explain it - thank you

sealake101:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 good job @sealake101 so in this way step by step please explain it - thank you \(\color{#0cbb34}{\text{End of Quote}}\) yep

sealake101:

ok so like how r they alike ... if u flip the bottom triangle around so its up ward like triangle GCB what can u tell

sealake101:

so like in your head can you make the triangle BPE fit in GCB?

Kenia:

I could tell their similar by using proportians

sealake101:

ok yeah i didnt know if u were familiar with proportions or not so how can u tell?

Kenia:

I would have to cross multiply but dk what numbers

sealake101:

ok so CB/CG = PB/PE if that helps

sealake101:

@jhonyy9 is that right?

jhonyy9:

so just a little attention please bc. you dont know the length of corresponding sides not can be used the proportionality of corresponding sides

Kenia:

wow I had that written down

Kenia:

it would be 300/350=200/x233+1/3 feet

jhonyy9:

@sealake101 but using this proportionalitie what you ve wrote above you can calcule the length of side PE but this not is for part A.

sealake101:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 @sealake101 but using this proportionalitie what you ve wrote above you can calcule the length of side PE but this not is for part A. \(\color{#0cbb34}{\text{End of Quote}}\) ok

jhonyy9:

ok little help what are these similar triangles ?

jhonyy9:

please collaborate

sealake101:

GCB and EPB are similar triangles is what we agreed on right Kenia

Kenia:

yes

jhonyy9:

yes so and now we need to prove the similarity of these triangles how ?

jhonyy9:

what you know about 2 opposite angles formed by two lines - how are ?

Kenia:

they are formed by two lines intersecting

jhonyy9:

yes of corse - so there on this image let be angle B_1 and opposite to this let be angle B_3 - formed by line GE and line CP

jhonyy9:

how are these angles ?

Kenia:

you typed angle b1 and angle b3?

jhonyy9:

yes

jhonyy9:

we not them in this way

jhonyy9:

@sealake101

jhonyy9:

ok ?

sealake101:

sorry im trying to do my science too but yea

jhonyy9:

ok and did you heard about alternate interior and alternate exterior angles ?

sealake101:

yes, i did

jhonyy9:

formed by a line and two parallel lines - yes ? ok so how are these angles ?

jhonyy9:

on this image there are lines GR and PC - parallel and intersected by line GE what are there these alternate interior angles what we can use to prove the similarity of these two triangles ?

sealake101:

because of alternate interior angles, it shows that angle G is congruent to angle E

Kenia:

sorry im back

sealake101:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Kenia sorry im back \(\color{#0cbb34}{\text{End of Quote}}\) ok so do u know about alternate interior and alternate exterior angles ?

Kenia:

yea a bit

jhonyy9:

|dw:1605894706390:dw|

sealake101:

wow u really just did that all lol

jhonyy9:

yes of corse and now look on this image hope will be more understandably about what i talk

jhonyy9:

@Kenia the similarity of these triangles is clearly now ?

jhonyy9:

part C. ?

jhonyy9:

just use the proportionality of corresponding sides @sealake101

jhonyy9:

what are these ways ?

Kenia:

wait so what is the answer exactly

jhonyy9:

where for what ?

sealake101:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Kenia wait so what is the answer exactly \(\color{#0cbb34}{\text{End of Quote}}\) for part b?

Kenia:

for B

jhonyy9:

@sealake101 do you can calcule these distances ?

jhonyy9:

ok so for part B. @sealake101 can you clarify the similarity of triangles ?

sealake101:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 ok so for part B. @sealake101 can you clarify the similarity of triangles ? \(\color{#0cbb34}{\text{End of Quote}}\) yeah ok so because of vertical angles are congruent the two angles are congruent...that is what I would put

jhonyy9:

ok so what similariity theorem was used there than ?

sealake101:

hey ill brb

jhonyy9:

did you heard about SAS or SSS or ASA ... and so much

jhonyy9:

@Kenia

Kenia:

yes still learning

jhonyy9:

ok and in case of your posted problem what theorem we used ?

Kenia:

Idk if it was ASA or SAS

jhonyy9:

what mean this S from there ?

Kenia:

wym

jhonyy9:

what mean this ASA ?

jhonyy9:

so similarity by angle - side - angle ok ?

Kenia:

yes

jhonyy9:

and now please look on my above posted image - i ve noted there similar 3 angles - yes ? so without any sides than in this case what theorem of similarity we can use there ?

jhonyy9:

so SSS - what mean side-side - side ?

Kenia:

yes side side side postulate

jhonyy9:

3 angles how you can note ?

jhonyy9:

no

jhonyy9:

there are not any sides

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 3 angles how you can note ? \(\color{#0cbb34}{\text{End of Quote}}\)

jhonyy9:

AAA

jhonyy9:

same with SSS just here we have 3 angles and not sides ok ?

jhonyy9:

and now for part C.

Kenia:

wait so

Kenia:

the final is 3 angles with no sides

jhonyy9:

distance BE and PE

jhonyy9:

yes angle - angle -angle similarity theorem

jhonyy9:

sorry i gtg but i come back in a 20 min.

sealake101:

sorry i had to take my puppy outside ...

Kenia:

ok

Kenia:

that's fine

jhonyy9:

@sealake101 please help continue - and i will come to check it - thank you

sealake101:

ok

sealake101:

ok so r u already on partC ?

Kenia:

yea give me a minute to type this down

sealake101:

ok

sealake101:

u good now?

Kenia:

it wasn't letting me type sorry

Kenia:

yea

sealake101:

ok so what all did u get to for this part?

Kenia:

part C?

sealake101:

yes

Kenia:

we were about to start then he left

sealake101:

ok so finding the distance from B to E and from P to E you will have to find a ratio or proportion

Kenia:

ok

sealake101:

so like what i put up earlier ...

sealake101:

CB/CG = PB/PE

sealake101:

right?

Kenia:

yes I have that

sealake101:

ok did u fill it in yet?

Kenia:

yes

sealake101:

ok what did u get?

Kenia:

300/350=200/x 233+ 1/3 feet

sealake101:

yes

sealake101:

do u know what to do next?

Kenia:

holdup

sealake101:

k

sealake101:

tell me when u get it

Kenia:

I will

sealake101:

kk

sealake101:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Kenia 300/350=200/x 233+ 1/3 feet \(\color{#0cbb34}{\text{End of Quote}}\) wait hold on...

sealake101:

where did u get 300 and 200 it should be 400 and 250...

Kenia:

you're right omg no wonder I was stuck

Kenia:

wait so 400/350=250/x 233?

sealake101:

idk where u got them numbers

sealake101:

400/350=450/250

sealake101:

sorry gtg

Kenia:

oh ok thanks for ur help

jhonyy9:

ok i m

Kenia:

hiii

jhonyy9:

did you solved the part C. ?

Kenia:

so far I have CB/CG=PB/PE which is 400/350=250/x 233+ 1/3 feet I just need to solve it

jhonyy9:

400/350 = 250 /x yes and now solve this for x

jhonyy9:

\[\frac{ 400 }{ 350 } = \frac{ 250 }{ x }\] cross multiplie and so what you get ?

jhonyy9:

are you here ?

Kenia:

yea im typing it down sorry

Kenia:

so that would be

Kenia:

400x

Kenia:

would I have to multiply 250 and 350

jhonyy9:

yes 400x = 250*350 and from there how you get the x ?

jhonyy9:

any idea ?

Kenia:

that would be 87,500

jhonyy9:

what is this ?

Kenia:

250x350

jhonyy9:

sorry but i ve dont said to you to multiplie

jhonyy9:

there is 400x = 250*350 hoe you get the x ?

jhonyy9:

how

jhonyy9:

divide both sides by 400 and will get in this way what ?

Kenia:

divide 400 with 250 and 350?

jhonyy9:

there are 400x = 250*350 divide both sides by 400 and will get \[\frac{ 400x }{ 400 } = \left( \frac{ 250*350 }{ 400 } \right)\]

jhonyy9:

and now ?

jhonyy9:

in the left part simplify the 400 by 400 and remain just x yes ?

jhonyy9:

in the right part how will be ?

jhonyy9:

alo

Kenia:

yes

jhonyy9:

250*350 / 400 = ?

jhonyy9:

what can you simplify there ?

Kenia:

I thought it would be x instead of 400

Kenia:

ohh

Kenia:

wait ok

Kenia:

875/4

jhonyy9:

how you get this ?

jhonyy9:

250*350 = 25*35*100 yes ?

Kenia:

I input it in the calculator

jhonyy9:

no in your head

jhonyy9:

so this is ok ? 25*35*100 in numerator yes ?

Kenia:

I don't get it

jhonyy9:

bc. 250 = 25*10 and 350 = 35*10 25*10*35*10 = 25*35*10*10 = 25*35*100 yes ?

jhonyy9:

ok ?

Kenia:

im still confused

jhonyy9:

so than there will be ok this is just for you than you wan make calcule without calculator

jhonyy9:

so than x = ?

Kenia:

yes

jhonyy9:

so than PE = ?

Kenia:

um

Kenia:

I still only have 400x/400=(250×350/400)

jhonyy9:

yes but from there we ve got x = 250*350/400 = ?

jhonyy9:

this is the distance of PE

Kenia:

idk how I would calculate that

jhonyy9:

875/4 have got above

Kenia:

oh so I was right

jhonyy9:

218,75 and 875/4 = 218,75 yes you was right

jhonyy9:

so and now the second distance

jhonyy9:

how you get the BE using proportionality of corresponding sides ?

Kenia:

so that was P to E

jhonyy9:

yes

Kenia:

ok

jhonyy9:

and now the BE

jhonyy9:

what proportional sides can we use for BE ?

jhonyy9:

look please on the line CP and GE CP formed by what segments ? and GE formed by what segments ?

Kenia:

ge is 450

jhonyy9:

no this is just GB

Kenia:

ohh

jhonyy9:

so than you look on this image - you see that GE formed from GB and BE and CP formed from CB and BP yes ?

jhonyy9:

ok ?

Kenia:

ok back

jhonyy9:

so using the proportionality of corresponding sides we can write GB/BE = CB / BP

Kenia:

so this is different?

jhonyy9:

why different ? now you need calcule the distance from B to E

Kenia:

what would the numbers be exactly

jhonyy9:

GB/BE = CB / BP substitute the length in this equation for what you know

jhonyy9:

GB = ?

jhonyy9:

CB= ?

jhonyy9:

BP=?

jhonyy9:

look on this image pls

Kenia:

I am

Kenia:

still a lil confused

jhonyy9:

you need use the length given from there

Kenia:

ok

jhonyy9:

than substitute the length what given there inside this GB/BE = CB / BP

Kenia:

wait

Kenia:

GC/BE= CB/BP you said it was this

jhonyy9:

no GC there i ve wrote GB

jhonyy9:

the length of GB = ?

Kenia:

im so confused

Kenia:

ok I input that

jhonyy9:

GB/BE = CB / BP so please write these with numbers - lengths what you know

Kenia:

idk the numbers

jhonyy9:

look on the posted attached image

Kenia:

ok

Kenia:

gb is 450?

jhonyy9:

GB = 450 ft CB=350ft BP=250ft

jhonyy9:

GB/BE = CB / BP

jhonyy9:

how you get from there the BE ?

jhonyy9:

cross multiplie what you get ?

Kenia:

im trying to set them up in fractions

jhonyy9:

ok

Kenia:

so it would be

Kenia:

450/350=250/x

jhonyy9:

nor really 450/x = 350/250

jhonyy9:

so and from these now calcule the x value

jhonyy9:

cross multiplie what will get ?

Kenia:

350x

jhonyy9:

350x = ?

Kenia:

450x250?

jhonyy9:

yes 350x = 450*250 and now from this you need to calcule the x value

Kenia:

that would be 112,500

jhonyy9:

what ? the x ?

Kenia:

no 450x250

jhonyy9:

ok but you need the x

jhonyy9:

350x = 450*250 to get the x separate divide both sides by 350 and will get in this way for x x = ?

Kenia:

ok so

jhonyy9:

x = 450*250/350 = ?

jhonyy9:

so BE = ?

Kenia:

2250/7

jhonyy9:

450*25/35 450*5/7 2250/7 = ?

jhonyy9:

BE = ?

jhonyy9:

just divide the 2250 by 7 and will get the right answer hope helped have a nice day bye bye

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