Question

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than three times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. The following system of equations models this scenario:

4x = 8 + 3y
x − 2y = −3

What was the temperature of City A and City B on that day?

City A was 5° C, and City B was 4° C.
City A was 3° C, and City B was −1° C.
City A was 8° C, and City B was −3° C.
City A was 5° C, and City B was −5° C.

Answer 1

@ramen

Answer 2

Did u even read the lesson?

Answer 3

its ight i have all a's

Answer 4

Solve the second equation for x
x − 2y = −3
x − 2y+2y = −3+2y ..... adding 2y to both sides
x = 2y-3

Then plug this into the first equation
4x = 8 + 3y
4(x) = 8 + 3y
4(2y-3) = 8+3y ... replace x with 2y-3

I'll let you solve for y

Answer 5

Try graphing this equation.

Answer 6

https://www.desmos.com/calculator

Answer 7

type the equation from the problem into the graphing calculator

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ramen
https://www.desmos.com/calculator
\(\color{#0cbb34}{\text{End of Quote}}\)
use this

Answer 9

i still dont know what im doing

Answer 10

ok i show you graph

Answer 11

okay

Answer 12

where do the 2 equations cross?

Answer 13

what coordinate?

Answer 14

x=4 y=5

Answer 15

yep and which of those answer choices have those numbers?

Answer 16

a

Answer 17

okay

Answer 18

yassssss

Answer 19

smarty pants

Answer 20

yup