Question

A lawn-mowing company is trying to grow its business. It had 30 clients when they started its business and wants to increase by 6 new clients each week. Use an arithmetic sequence to write a function to represent this real-world situation and determine the range of the function for the first four weeks of data.

f(x) = 6x + 30; 0 ≤ y ≤ 4
f(x) = 6x + 24; 0 ≤ y ≤ 4
f(x) = 6x + 30; 30 ≤ y ≤ 48
f(x) = 6x + 24; 30 ≤ y ≤ 48

Answer 1

what do you mean

Answer 2

So basically, they start with 30 clients, so 30 is the y-intercept.
Now it wants to increase by 6 new clients per week so that is the slope
Also we want to determine the range from week zero to week 4. Given these 3 pieces of info what can you say?

Answer 3

also one more thing
f(x) = 6x + 30; 0 ≤ y ≤ 4
f(x) = 6x + 24; 0 ≤ y ≤ 4
f(x) = 6x + 30; 30 ≤ y ≤ 48
f(x) = 6x + 24; 30 ≤ y ≤ 48
For this part above, is it a typo or does it actually say 0 < y < 4 not x instead of y?

Answer 4

i think it would be the second answer

Answer 5

hmm, why do you say that?

Answer 6

Since we need to find the range for the first 4 weeks, it is not answer choice 2, this is because we want to find the range (also this is the most wrong answer choice, if you payed attention it doesn't have the correct y-intercept), if we plug in 0 for x we get 30, if we plug 4 we get 54. Now idk why 30 < y < 54 isn't an answer choice so I am assuming that you typed the thing wrong? as in instead of 0< y < 4 you meant x, (not y) so in that case what is the correct answer choice?

Answer 7

I can't further help if your gonna leave... Just saying ¯\_(ツ)_/¯