Question

Given a regular square pyramid with RS = 6 and PX = 4, find the following measure.
XT =
https://cdn.lti.glynlyon.com/media/f3ddd177-12c6-49af-8032-a6158fc4926a/img/groupi93.gif

Answer 1

I think its 3 sqrt of 2 but idk try it see if it works ok?

Answer 2

so given RS = 6 and PX = 4

bc. RS = ST = 6 => YT = 6/2 = 3 and
bc. RS = 6 => XY = 6/2 = 3

bc. given that RSTQ is a square and hope you know that the diagonales of a square are perpendicular on each other so from this result that from this triangle XYT you can calcule easy the length of XT

hope helped