a) Three sides of a triangle are 5, 6, and 8. Calculate the angles of the triangle. (b) Two sides of a triangle are 6 and 9. The angle between them is 30◦ . Calculate the length of the third side and find the missing angles. (c) One side of a triangle is 9. The angles at the endpoints of this side are 30◦ and 45◦ . Calculate the length of the other two sides. (d) Two sides of a triangle are 8 and 10. The angle opposite to the longer side is 60◦ . Calculate the length of the third side and find the missing angles (College Geometry) One question takes like 15 min and im really stressing rn if u can help may the universe return you the favor
a. do you can draw this triangle ?
Hmm?
so what you need to use there to calcule the angle measures of this triangle the law of sin ,or the law of cos or the law of tan have you learn about these ?
|dw:1607114848925:dw|
any idea now ?
using the law of sin you can write \[\frac{ \sin a }{ 6 } = \frac{ \sin b }{ 8 } = \frac{ \sin c }{ 5 }\]
im following ur steps ty
ok the next can you solve ?
Ill try
|dw:1607115671494:dw|
do you know the value of sin 30° ? this will help you a lot
I see
note the length of BC an ,,a" and write using the law of sin do you can use what i ve wrote above on the first problem ?
\[\frac{ \sin 30 }{ a } = \frac{ \sin B }{ 9 } = \frac{ \sin c }{ 6 }\]
Ok thanks man i appreciate ur help
yw my pleasure anytime
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 \[\frac{ \sin 30 }{ a } = \frac{ \sin B }{ 9 } = \frac{ \sin C }{ 6 }\] \(\color{#0cbb34}{\text{End of Quote}}\)
c. |dw:1607178321400:dw| so using this image you can write easy the length of these two sides
d. |dw:1607178875533:dw| hope this image will help you solve it easy
yes i finished it thx to u bro much appreciated
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