Question

Quadrilateral XENA is a parallelogram. T is the point of intersection of the
diagonals. Segment ET = y-1 and segment EA = 3y - 10. Solve for y.

PLZ HELP

Answer 1

do you can post an image about this parallelogram ?

maybe in this way ?

Answer 2

do you know the total sum of angle measure of a parallelogram equal how many ?

Answer 3

That's all it says, sorry.

Answer 4

ok but you know the sum of angle measure of a triangle equal how many ?

Answer 5

@Five

Answer 6

so the sum of angle measure of a triangle equal 180 degrees

using this how you think the sum of angle measure of a parallelogram how many will be ?

Answer 7

oh so y=18

Answer 8

how you get this value ?

Answer 9

(7x-5)+(3x+5)=180

Answer 10

(7(18)-5)=121

Answer 11

(3(18)+5)=59

Answer 12

no

you not can use this in this way because there are two triangles so the sum of angle measure of a parallelogram will be 2*180 = 360 degrees

ok ?

Answer 13

It says it's correct

Answer 14

sorry i dont know how can be correct

Answer 15

Same side interior angles.....idk it made no sense to me either but i guess i was suppose to look at it this way

Answer 16

(7x-5)+(3x+5)=180

so this you ve wrote above

and now just multiplie it by 2 bc. the sum of angle measure of a parallelogram is 360 degree

and in this way will get

2*[(7x-5) +(3x+5)] = 2*180

solve this please for x

Answer 17

this is the same how you solved the other one

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
so how i ve said these given angle measure doubled will give you 360 degrees

how can you write this using the given angle measures with y ?
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 19

7y-5 +3y+5 = 180

yes ?

Answer 20

and from this y = ?

Answer 21

If you plug the 18 in the values are correct and =180

Answer 22

yes of cors