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Mathematics 23 Online
XioGonz:

Some more geom.....

XioGonz:

1 attachment
KAPALOTJAY:

jesus

XioGonz:

@darkknight

KAPALOTJAY:

hoW much geometry-

XioGonz:

Some more..

darkknight:

LMO is going to be half of the intercepted arc LO, or half of 155 degrees

darkknight:

Remember from your earlier questions?

jimthompson5910:

\(\large \angle K = \frac{ \text{far arc} - \text{ near arc}}{2}\) Source: https://www.mathwarehouse.com/geometry/circle/tangents-secants-arcs-angles.php

jimthompson5910:

So in your case, you need to compute: \(\large \angle M = \frac{\text{ arc LO } - \text{ arc LN }}{2}\)

darkknight:

Oh right, i saw the diagram wrong, jim is correct.

XioGonz:

ah I see, Thank you!!

darkknight:

|dw:1607557840900:dw| I saw it like the black one, but its the red one.

XioGonz:

I see what happened, it's okay lol

darkknight:

If you ever have a scenario like red one, then refer to the formula jimthompson provided, for the black one, the intercepted arc is twice the inscribed angle

XioGonz:

For sure, thank you I will

ToxicaDennisIce:

so yea

starbucksgirl13:

umm hii

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