Some more geom.....
jesus
@darkknight
hoW much geometry-
Some more..
LMO is going to be half of the intercepted arc LO, or half of 155 degrees
Remember from your earlier questions?
\(\large \angle K = \frac{ \text{far arc} - \text{ near arc}}{2}\) Source: https://www.mathwarehouse.com/geometry/circle/tangents-secants-arcs-angles.php
So in your case, you need to compute: \(\large \angle M = \frac{\text{ arc LO } - \text{ arc LN }}{2}\)
Oh right, i saw the diagram wrong, jim is correct.
ah I see, Thank you!!
|dw:1607557840900:dw| I saw it like the black one, but its the red one.
I see what happened, it's okay lol
If you ever have a scenario like red one, then refer to the formula jimthompson provided, for the black one, the intercepted arc is twice the inscribed angle
For sure, thank you I will
so yea
umm hii
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