Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠ ROP

(6x − 4)° + (2x + 16)° = 180°
(6x − 4)° + (2x + 16)° = 360°
(x + 16)° + (6x − 4)° = 180°
(x + 16)° + (6x − 4)° = 360°

Question

Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠ ROP

(6x − 4)° + (2x + 16)° = 180°
(6x − 4)° + (2x + 16)° = 360°
(x + 16)° + (6x − 4)° = 180°
(x + 16)° + (6x − 4)° = 360°

ghostrider · Answer

attachment

supie · Answer

Ok well

The figure shows $$∠ROP + ∠RQP = 180˚$$ $$(x + 16)° + (6x - 4)° = 180$$
Does that help?