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The population of a village increases by 10% every year. If the present population is 6000, what will be the population of the village after 3 years? Solution: The present population P = 6000, Rate (r) = 10 Unit of time being year (n) = 3 Q = P(1 + r100)n ⟹ Q = 6000(1 + 10100)3 ⟹ Q = 6000(1 + 110)3 ⟹ Q = 6000(1110)3 ⟹ Q = 6000 × (1110) × (1110) × (1110) ⟹ Q = 7986 Therefore, the population of the village will be 7986 after 3 years.
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