Anyone mind helping?- {Screen shot will be posted below}
\[6(2/1)/1\]
Order of Operations.= PEMDAS 1.parentheses, 2.exponents, 3.multiplication, 4.division, 5.addition, 6.subtraction
So, \[2\div 1=2\]
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Imagine So, \[2\div 1=2\] \(\color{#0cbb34}{\text{End of Quote}}\) Uh-huh.
\[6\times 2\div 2\]
You do mutiplication first due to pemdas.
\[6\times 2=12\]
\[12\div 2=6\]
All done!
For the Second Problem,
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Imagine \[12\div 2=6\] \(\color{#0cbb34}{\text{End of Quote}}\) Oh I thought it was 2 divided 2. ;-; MY FAULT
\[(7+2^3)\times 9\]
Parentheses first due to Pemdas
270?
Bruh I keep forgetting. ;-;
7+2=9
\[9^3\times 9\]
Then do Exponets.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Imagine \[9^3\times 9\] \(\color{#0cbb34}{\text{End of Quote}}\) 81?
\[9^3=729\]
\[792\times 9=7128\]
All Complete!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Imagine All Complete! \(\color{#0cbb34}{\text{End of Quote}}\) Thank you so much!!
Anytime, That's what I'm here for!
Do you have anymore question's for me?
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