Question

Polynomial long division.

Answer 1

do you have a specific problem?

Answer 2

https://youtu.be/8lT00iLntFc

Answer 3

(2x^3-8x^2+9x-2) divided by (x-2)

Answer 4

Write remainders as fractions.

Answer 5

ok lemme solve this out real quick, gimmie like 1 minute

Answer 6

Okay

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Allison
(2x^3-8x^2+9x-2) divided by (x-2)
\(\color{#0cbb34}{\text{End of Quote}}\)
How do ya'll work this out?

Answer 8

All you have to do is solve the stuff in parenthesis and divide by 2

Answer 9

Oh, Thanks.

Answer 10

ok so first step is to make sure it's in Ax^2+Bx+c form. In this case it is seeing as we start with an exponent of 3 then we go to an exponent of 2 then 1 then a constant.
so then we need to set up our problem.

follow so far?

Answer 11

Okay

Answer 12

ok so now we solve.
we are going to take the FIRST term from the denominator and see what we need to multiply it by to get the first term of the numerator. We will place this number above the corresponding term and then multiply it by both terms in the denominator. This sounds confusing, ik, sorry. Here's a visual. Let me know if it doesn't make sense

Answer 13

so we did x times what is equal to 2x^3? it would be 2x^2, so we write it above the terms that has x^2 in it. do you follow?

Answer 14

Yes

Answer 15

ok so then we do the same steps as if we were doing regular long division. Now we are going to repeat. Now x times what is going to be equal to -4x^2? do you need me to give you the visual or do you want to try it?

Answer 16

Just keep doing it so I can take notes lol

Answer 17

lmaooo ok. so continuing, we need to know what times x is going to be -4x^2.we get -4x,so we write it above the term containing an "x" and we multiply. we get x-2. Now, what times x is 1x? the answer is going to be 1. so we write this about our constant, and multiply. Then we will end up with our answer, and in this case,we have no remainder so our answer is just 2x^2-4x+1

Answer 18

i can give you an example of one with a remainder if you need it as well.

Answer 19

Thank you lots <3

Answer 20

you're welcome <3