Question

NEED HELP
Rita divides Avogadro’s number (approximately 6.02214 Times. 10>23) by 2.055 to calculate the number of atoms in a sample.
Which expression gives her result to the correct number of significant figures?

A. 2.93 Times. 10>23
B. 2.930 Times. 10>23
C. 2.9305 Times. 10>23
D. 2.93048 Times. 10>23

Answer 1

as the problem states, divide 6.02214 * 10^(23) / (2.055)

as for sig figs: Avogadro's number is treated as a constant with infinite sig figs, so 2.055 is your limiting sig fig determinant. since 2.055 has 4 sig figs, your answer should also have 4 sig figs.

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
as the problem states, divide 6.02214 * 10^(23) / (2.055)

as for sig figs: Avogadro's number is treated as a constant with infinite sig figs, so 2.055 is your limiting sig fig determinant. since 2.055 has 4 sig figs, your answer should also have 4 sig figs.
\(\color{#0cbb34}{\text{End of Quote}}\)
Thanks friend.