Question

-x^2+9x-18=

Answer 1

So we have to factor them...\[−x^2+9x−18=\]\[(−x+3)(x−6)\]
Yes?

Answer 2

Yes

Answer 3

I believe so

Answer 4

"should we" lmao

Answer 5

XDD

Answer 6

Ok well \[(−x+3)(x−6)=\]\[(−x+3)(x+−6)=\]\[(−x)(x)+(−x)(−6)+(3)(x)+(3)(−6)=\]\[−x^2+6x+3x−18\]\[−x^2+9x−18\]

Answer 7

-x^2+9x-18=

what are you trying to do? factor and find zeros?

Answer 8

Um factor idek

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) supie
So we have to factor them...\[−x^2+9x−18=\]\[(−x+3)(x−6)\]
Yes?
\(\color{#0cbb34}{\text{End of Quote}}\)
then yeah supie did that god job supie

Answer 10

god?

Answer 11

XDD ty Supie

Answer 12

Thanx Darkknight

and np!