Question

Given:
AD = BC


Prove:
A = B

1. AD = BC, BC⊥AE, AD⊥BE

2. ∠D and ∠C are right angles

3. ∠E = ∠E

4. Triangle ADE congruent to Triangle BCE

5. ∠A = ∠B

Reflexive
Perpendicular lines form right angles.
Given
CPCTE
LA

Answer 1

given

1. AD = BC, BC⊥AE, AD⊥BE
from what result <D = <C right angles

<E common angle

<D = <C
= > <A = < B => triangle BCE congruent triangle ADE => <A = <B
< E = <E

Answer 2

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