Question

The graph below shows four straight lines, A, B, C, and D:

graph of line A going through ordered pairs negative 2, negative 3 and 2, 5. Graph of line B going through ordered pairs negative 2, negative 4 and 2, 4. Graph of line C going through ordered pairs negative 2, negative 5 and 3, 5. Graph of line D going through ordered pairs 0, negative 4 and 4, 4

Which line is represented by the function f(x) = 2x + 1? (1 point)

Line A
Line B
Line C
Line D

Answer 1

i am assuming its b am i correct

Answer 2

the graph tho-

Answer 3

- so just you need check these coordinates of given points need to be roots of this given equation

Answer 4

b. not is right

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
b. not is right
\(\color{#0cbb34}{\text{End of Quote}}\)
so ur saying b is right?

Answer 6

lol

Answer 7

Ik it
🤣

Answer 8

b. not is

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
b. not is
\(\color{#0cbb34}{\text{End of Quote}}\)
its not but is

Answer 10

What

Answer 11

🤣🤣🤣

Answer 12

line B going through ordered pairs negative 2, negative 4 and 2, 4

check please these points are or not roots of given equation of f(x) = 2x + 1

Answer 13

bruh

Answer 14

(-2,4) and (2,4)

Answer 15

bye

Answer 16

for x = -2 will get y = 4 or f(x) = 4 ?

Answer 17

byeeeeeee

Answer 18

or for (2,4)
so for x=2 will get y = 4 ???

Answer 19

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
or for (2,4)
so for x=2 will get y = 4 ???
\(\color{#0cbb34}{\text{End of Quote}}\)
i think i need to hire u as a tutor

Answer 20

🙄🙄🙄🙄🙄🙄🙄

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MIACupcake
🙄🙄🙄🙄🙄🙄🙄
\(\color{#0cbb34}{\text{End of Quote}}\)
whttttt this dude @jhonyy9 is smarttttt

Answer 22

f(x) = 2x + 1

how you get for x=2 this y=4 ?

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @KayleeElizabeth0419
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
or for (2,4)
so for x=2 will get y = 4 ???
\(\color{#0cbb34}{\text{End of Quote}}\)
i think i need to hire u as a tutor
\(\color{#0cbb34}{\text{End of Quote}}\)
sorry what mean this ?

Answer 24

hire u ?

Answer 25

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
\(\color{#0cbb34}{\text{Originally Posted by}}\) @KayleeElizabeth0419
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
or for (2,4)
so for x=2 will get y = 4 ???
\(\color{#0cbb34}{\text{End of Quote}}\)
i think i need to hire u as a tutor
\(\color{#0cbb34}{\text{End of Quote}}\)
sorry what mean this ?
\(\color{#0cbb34}{\text{End of Quote}}\)
its a joke i was sayingggggg i could use ur help wit math sum times bc i juss dont know bc im dum dum

Answer 26

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
hire u ?
\(\color{#0cbb34}{\text{End of Quote}}\)
no i need your help sum times wit math

Answer 27

really ???

ok anytime when you like

Answer 28

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
really ???

ok anytime when you like
\(\color{#0cbb34}{\text{End of Quote}}\)
okkk thx broski

Answer 29

broski ??? what mean ? sorry i dont understand

Answer 30

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
broski ??? what mean ? sorry i dont understand
\(\color{#0cbb34}{\text{End of Quote}}\)
its the same thing as bro lol

Answer 31

ok ty indifferent always i m glad to help - give help in what i can - lol

Answer 32

just tag me when you need and than i m online i will try help you

Answer 33

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
just tag me when you need and than i m online i will try help you
\(\color{#0cbb34}{\text{End of Quote}}\)
okkk sounds good