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Mathematics 17 Online
Nameless:

Calculate the area of the irregular polygon shown below: Image of letter E with height of 12 and width of 7 and inside space of height of 5 and width of 6. All units are in inches. 24 square inches 44 square inches 54 square inches 84 square inches

TETSXPREME:

picture?

TETSXPREME:

24

Nameless:

Woah

Nameless:

Fast

TETSXPREME:

huh?

TETSXPREME:

Yw :>

Nameless:

u fast

Nameless:

at solving

TETSXPREME:

yessir

sak123:

I wanted to help

akeelahmeans:

me to

XioGonz:

Given: Image of letter E H=12 and W=7 Inside space:height of 5 and width of 6 Calculate the area of rectangle ABKL = length *width = 12*7= 84 square inches Subtract the area of rectangle CDFE and HGJI from the rectangle ABKL Area of CDEF = Area of HGJI Area of CDEF = length *width =5*6 = 30 square inches So the area of HGJI = 30 square inches Subtract the area of both rectangles from the area ABKL 84-(30+30) = 24 square inches . So it is 24 square inches .

XioGonz:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @TETSXPREME 24 \(\color{#0cbb34}{\text{End of Quote}}\) Refrain from giving direct answers.

akeelahmeans:

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