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Mathematics 17 Online
DaddyClause:

help with math please

DaddyClause:

1 attachment
DaddyClause:

@jhonyy9 @Laylalyssa @darkknight

sak123:

what do you think the answer is?

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @sak123 what do you think the answer is? \(\color{#0cbb34}{\text{End of Quote}}\) i really dont know

DaddyClause:

can sb help

sak123:

ok

jhonyy9:

do you know what mean ,,conjugate of " ?

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 do you know what mean ,,conjugate of " ? \(\color{#0cbb34}{\text{End of Quote}}\) kinda not really tho

jhonyy9:

you need eliminate the term of i from denominator so in this way you need multiplie top and bottom by conjugate of denominator

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 you need eliminate the term of i from denominator so in this way you need multiplie top and bottom by conjugate of denominator \(\color{#0cbb34}{\text{End of Quote}}\) ok thank you

jhonyy9:

so what will be the conjugate of 8 +2i ?

DaddyClause:

10?

jhonyy9:

no by what term you need multiplie the 8+2i to eliminate the term of i ?

jhonyy9:

use formula a^2 -b^2 = (a-b)(a+b)

DaddyClause:

oh then the answer is 8+2i

jhonyy9:

no

DaddyClause:

no\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 \(\color{#0cbb34}{\text{End of Quote}} im so confused

jhonyy9:

you need multiplie the 8+2i by conjugate to elimine the term of i

jhonyy9:

using formula a^2 -b^2 =(a-b)(a+b) 8+2i multiplie by 8-2i so what will get ?

DaddyClause:

2i+8 =8+2i

xxDeppressionxx:

It is 3/8 – 5i/2 because if you do +,- then you get negative right? or is it the other way around

jhonyy9:

multiplie top and bottom by 8 -2i

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 multiplie top and bottom by 8 -2i \(\color{#0cbb34}{\text{End of Quote}}\) ight

jhonyy9:

so what will get ?

jhonyy9:

(3-5i)(8-2i)= ?

DaddyClause:

i tried divide and multiply just in case

jhonyy9:

and in denominator will be (8-2i)(8+2i) = 64 - (-4) = ?

DaddyClause:

multiply-14 - 46 i

DaddyClause:

divide-3 + 1.37500 i

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 (3-5i)(8-2i)= ? \(\color{#0cbb34}{\text{End of Quote}}\) so this will be 24 -6i -40i +10(-1) = 24 -46i -10 = 14 -46i this will get in numerator

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 \(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 (3-5i)(8-2i)= ? \(\color{#0cbb34}{\text{End of Quote}}\) so this will be 24 -6i -40i +10(-1) = 24 -46i -10 = 14 -46i this will get in numerator \(\color{#0cbb34}{\text{End of Quote}}\) ok

jhonyy9:

\[\frac{ 14 -46i }{ 68 } = ?\]

jhonyy9:

by what can you simplifie top and bottom ?

jhonyy9:

by 2 and so will get \[\frac{ 7 -23i }{ 34 }\]

DaddyClause:

sorry it lagged me out

jhonyy9:

do you see now the right choice ?

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 do you see now the right choice ? \(\color{#0cbb34}{\text{End of Quote}}\) yes thank u so much

DaddyClause:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 do you see now the right choice ? \(\color{#0cbb34}{\text{End of Quote}}\) i appreciate it

jhonyy9:

np anytime

jhonyy9:

bye bye

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