Question

Can anyone help me with Factoring Polynomials?
Factor 3x3 - x2y +6x2y - 2xy2 + 3xy2 - y3 =
(3x - 2y)(x + y)
(3x - y)(x + y)(x - y)
(3x - y)(x + y)2
(3x - y)(x2 + y2)
(college pre-grad)

Answer 1

@justus

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @umm
@justus
\(\color{#0cbb34}{\text{End of Quote}}\)
i dmed justus

Answer 3

yea

Answer 4

\[3x^3-x^2y+6x^2y-2xy^2+3xy^2-y3\]

\[(3x^3-x^2y)+(6x^2y-2xy^2)+(3x^2-y^3)\]

\[ x^2(3x-y)+2xy(3x-y)+y^2(3x-y)\]

\[(3x-y)(x^2+2xy+y^2)\]

\[= (3x-y)(x+y)^2\]

Answer 5

u need help with that

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Emily488
u need help with that
\(\color{#0cbb34}{\text{End of Quote}}\)
yes

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @justus
\[3x^3-x^2y+6x^2y-2xy^2+3xy^2-y3\]

\[(3x^3-x^2y)+(6x^2y-2xy^2)+(3x^2-y^3)\]

\[ x^2(3x-y)+2xy(3x-y)+y^2(3x-y)\]

\[(3x-y)(x^2+2xy+y^2)\]

\[= (3x-y)(x+y)^2\]
\(\color{#0cbb34}{\text{End of Quote}}\)
thank you so much

Answer 8

No problem <3

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @justus
No problem <3
\(\color{#0cbb34}{\text{End of Quote}}\)
i have more....

Answer 10

easy tell me the intructions

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Emily488
easy tell me the intructions
\(\color{#0cbb34}{\text{End of Quote}}\)
eeeh just google Factoring Polynomials....but idk how old you are but it is college math so dont be upset if you dont understand it

Answer 12

ok i will

Answer 13

im 16