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A 46 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1368. N = N0e -kt N0 = initial mass (at time t = 0) N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days Find the substance's half-life, in days. Round your answer to the nearest tenth
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oboof
N(t) = (Nø) • e^[- k • t ] 23 = (½) • (46) half-life 23 = (46) • e^- 0.137 • t divide by 46 0.5 = e^- 0.137 • t take the natural log of both side In 0.5 = - (0.137) • t (t = 5.06 days t = 5.1 days rounded to nearest tenth)
bruh u answer his but not minee :(
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