I just need this one equation solved so I can use this equation as a reference to solve the other equations. Question: Convert between standard and factored form and use both equations to determine the x and y intercepts: a) y = x^2 + x - 6
hmmmm
hmmmmmmmmm
the factored form how you get ? x^2 +Sx +P = 0 S = x_1 +x_2 P = x_1 *x_2 do you know these ?
no
try get two numbers with sum equal +1 and product equal -6
@Laylalyssa
do you know the way how you solve a quadratic equation ?
@supie
No that's why i'm asking for extra help
have you learn about discriminant ?
if no so than you need use the factorization method - about what i ve wrote above
please check it there
will do
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 the factored form how you get ? x^2 +Sx +P = 0 S = x_1 +x_2 P = x_1 *x_2 do you know these ? \(\color{#0cbb34}{\text{End of Quote}}\) you need get two numbers with sum equal +1 and product equal -6
..............
I am so confused....
If you need help still from there you can go to a website called khan academy because they provide all sorts of videos to help with any kind of math.
yeah
okay let me check out that website
for example a +b = 1 a*b = -6 solve it for a and b
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 for example 3 -2 = 1 3*(-2) = -6 yes ? \(\color{#0cbb34}{\text{End of Quote}}\)
and now how you write in factorized form your quadratic ?
x^2 +x -6 = ( x +3)(x -2) right ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 x^2 +Sx +P = 0 S = 3-2 = 1 P = 3*(-2) = -6 ok ? \(\color{#0cbb34}{\text{End of Quote}}\)
oh nvm i found a video on how to solve it thank you for the help though
np yw
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