Evaluate the expression \((4x^3y^{-2})(3x^{-2}y^4)\)
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use this property a^x *a^y = a^(x +y) and a^x : a^y = a^(x - y )
ok step by step 4*3 = ?
bravo who asked is offline
@Laylalyssa
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 ok step by step 4*3 = ? \(\color{#0cbb34}{\text{End of Quote}}\) 12
ok the second terms x^3 *x^(-2) = ?
use this formula what i ve wrote above
when you multiple the same terms with exponents so the exponents you need assume them
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 ok the second terms x^3 *x^(-2) = ? = x^(3-2) = x^? \(\color{#0cbb34}{\text{End of Quote}}\)
and in case of the next term of y just so in this way
@supie
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 \(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 ok the second terms x^3 *x^(-2) = ? = x^(3-2) = x^? \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{End of Quote}}\) so i just solve \(x^3 *x^(-2) = ? = x^(3-2)\)?
\(x^3 *x^{(-2)} = ? = x^{(3-2)}\)?
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