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Mathematics 12 Online
Astrid1:

Help? SS below:

Astrid1:

smackz:

what are we solving for

jkmiec26:

I think it would be h=12

jkmiec26:

if you multiply x by x they cancel out so I think it would be h=12

smackz:

u have to find the value of h

jkmiec26:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @smackz u have to find the value of h \(\color{#0cbb34}{\text{End of Quote}}\) like I said h=12

jkmiec26:

well I mean I think

smackz:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 well I mean I think \(\color{#0cbb34}{\text{End of Quote}}\) o;

smackz:

idk

jkmiec26:

@Astrid1 what grade r u in?

Astrid1:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 @Astrid1 what grade r u in? \(\color{#0cbb34}{\text{End of Quote}}\) 8th

jkmiec26:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 \(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 @Astrid1 what grade r u in? \(\color{#0cbb34}{\text{End of Quote}}\) 8th \(\color{#0cbb34}{\text{End of Quote}}\) mk

Astrid1:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 \(\color{#0cbb34}{\text{Originally Posted by}}\) @Astrid1 \(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 @Astrid1 what grade r u in? \(\color{#0cbb34}{\text{End of Quote}}\) 8th \(\color{#0cbb34}{\text{End of Quote}}\) mk \(\color{#0cbb34}{\text{End of Quote}}\) Okie, can you help meee?

jkmiec26:

with?

Astrid1:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 with? \(\color{#0cbb34}{\text{End of Quote}}\) nvm I didn't scroll up/

jkmiec26:

mk

jkmiec26:

is the answer right?

Astrid1:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jkmiec26 is the answer right? \(\color{#0cbb34}{\text{End of Quote}}\) Idk, I think so.

jkmiec26:

mk

jprince:

Is this Algebra1? because the problem reads h of x = 12 divided by x. Have you been given a value for x? You would substitute and solve. Otherwise x times x, is x to the power of 2. Then you need to take the square root of 12 to get your answer.

Astrid1:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jprince Is this Algebra1? because the problem reads h of x = 12 divided by x. Have you been given a value for x? You would substitute and solve. Otherwise x times x, is x to the power of 2. Then you need to take the square root of 12 to get your answer. \(\color{#0cbb34}{\text{End of Quote}}\) yes, this is algebra.

jprince:

The answer is the square root of 12. Do you know how to simplify that? How I got that?

jkmiec26:

@jprince u smart

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