Ask your own question, for FREE!
Mathematics 24 Online
helpmeout:

Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r)

nevaehhh:

Do you know the first step ?

nevaehhh:

Hint: you need to separate the variables, and add or subtract

MysticalDimpless:

Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp

katalina:

i am not that freaking smart

nevaehhh:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp \(\color{#0cbb34}{\text{End of Quote}}\) since you're new here, direct answers aren't allowed... you need to lead people, not tell them the answer

MysticalDimpless:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp \(\color{#0cbb34}{\text{End of Quote}}\) since you're new here, direct answers aren't allowed... you need to lead people, not tell them the answer \(\color{#0cbb34}{\text{End of Quote}}\) Ohh Im sorry and it's not a direct answer i explained it very well

nevaehhh:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless \(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp \(\color{#0cbb34}{\text{End of Quote}}\) since you're new here, direct answers aren't allowed... you need to lead people, not tell them the answer \(\color{#0cbb34}{\text{End of Quote}}\) Ohh Im sorry and it's not a direct answer i explained it very well \(\color{#0cbb34}{\text{End of Quote}}\) it is a direct answer, because you DIRECTLY gave them the answer.

MysticalDimpless:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless \(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp \(\color{#0cbb34}{\text{End of Quote}}\) since you're new here, direct answers aren't allowed... you need to lead people, not tell them the answer \(\color{#0cbb34}{\text{End of Quote}}\) Ohh Im sorry and it's not a direct answer i explained it very well \(\color{#0cbb34}{\text{End of Quote}}\) it is a direct answer, because you DIRECTLY gave them the answer. \(\color{#0cbb34}{\text{End of Quote}}\) They asked for it so i gave

nevaehhh:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless \(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless \(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp \(\color{#0cbb34}{\text{End of Quote}}\) since you're new here, direct answers aren't allowed... you need to lead people, not tell them the answer \(\color{#0cbb34}{\text{End of Quote}}\) Ohh Im sorry and it's not a direct answer i explained it very well \(\color{#0cbb34}{\text{End of Quote}}\) it is a direct answer, because you DIRECTLY gave them the answer. \(\color{#0cbb34}{\text{End of Quote}}\) They asked for it so i gave \(\color{#0cbb34}{\text{End of Quote}}\) it's against the rules.

MysticalDimpless:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless \(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless \(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh \(\color{#0cbb34}{\text{Originally Posted by}}\) @MysticalDimpless Simplify (2p+q) (p-2q+3r) - (p-3q) (-3p+q-2r) Solution: (2p + q) (p - 2q + 3r) - (p-3q) (-3p + q - 2r) → 2p (p - 2q + 3r) + q(p - 2q + 3r) - p(-3p + q - 2r) + 3q (-3p + q - 2r) → 2p² - 4pq + 6rp + pq - 2q² + 3qr + 3p² - pq + 2rp - 9qp + 3q² - 6qr → 2p² + 3p² - 2q² + 3q² - 4pq + pq - pq - 9pq + 3qr - 6qr + 6rp + 2rp → 5p² + q² - 13pq - 3qr + 8rp \(\color{#0cbb34}{\text{End of Quote}}\) since you're new here, direct answers aren't allowed... you need to lead people, not tell them the answer \(\color{#0cbb34}{\text{End of Quote}}\) Ohh Im sorry and it's not a direct answer i explained it very well \(\color{#0cbb34}{\text{End of Quote}}\) it is a direct answer, because you DIRECTLY gave them the answer. \(\color{#0cbb34}{\text{End of Quote}}\) They asked for it so i gave \(\color{#0cbb34}{\text{End of Quote}}\) it's against the rules. \(\color{#0cbb34}{\text{End of Quote}}\) Oh im srry

Amangami:

Prove:16cos12.cos24.cos48.cos84=1

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!