4x^2 - 64 = y
@jhonyy9
what is 4x^2?
use formula a^2 -b^2 = (a-b)(a+b)
idk what x is
its also vertex, forgot to add
there is a difference of two squares
so i need the ertex form for 4x62-64=y
(2x)^2 - 8^2 = ? use these above wrote formula
ohhhh
sqr root the other number
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Aqual sqr root the other number \(\color{#0cbb34}{\text{End of Quote}}\) mhm
ok so how do i put that in vertex form
cuz 2 is a prime number
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 use formula a^2 -b^2 = (a-b)(a+b) \(\color{#0cbb34}{\text{End of Quote}}\) use this
so (-6, 10)?
no, (10, -6)
cuz its -8
(2x -8)(2x +8) solve this for x
2x -8 = 0 x_1 = ? 2x +8 = 0 x_2 = ?
4, -4
try it like this 4*x^2-64-(y)=0
do 4(x^2 -16) then so it's 4(x-4)(x+4)
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