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Mathematics 19 Online
Epicpanda123:

Fat calories varies directly with the grams of fat. There are 27 calories for each 3 grams of fat.

Epicpanda123:

who understands what to do?

prettygirlgang:

i think im not very sure

mxddi3:

Welcome to QC. There isn't really a question here, just information. Are you missing parts of your question?

smackz:

whats the question here?

Astrid1:

I happened to find the answer, But first, What do you think the answer is? Also, what are your answer choices?

smackz:

Astrid he never gave an actual question he just told us some fact

Epicpanda123:

no this is the question that I got.

smackz:

@Astrid1

smackz:

^

mxddi3:

Ok well there are numerous things we could do with this question, so if there is nothing else, idk how to help you. As I said, there is no question there, just information, so we don't really have a task to do.

Epicpanda123:

nevermind I think I figured it out. Thank though

Astrid1:

Ehem Smackz Ik the answer to this, I searched google . EHEM. Also, What do you think the answer is tho?

Astrid1:

What we are supposed to do on this question is to determine the constant of variation for the direct variation that was given.

jhonyy9:

so bc. fat calories varies directly with the grams of fat you can write 27 = 3k where ,,k" mean the constant so to find the ,,k" value just divide both sides by 3 hope helped understandably easy @Laylalyssa

jhonyy9:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so bc. fat calories varies directly with the grams of fat you can write 27 = 3k where ,,k" mean the constant so to find the ,,k" value just divide both sides by 3 hope helped understandably easy @Laylalyssa \(\color{#0cbb34}{\text{End of Quote}}\) @XioGonz

XioGonz:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 \(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so bc. fat calories varies directly with the grams of fat you can write 27 = 3k where ,,k" mean the constant so to find the ,,k" value just divide both sides by 3 hope helped understandably easy @Laylalyssa \(\color{#0cbb34}{\text{End of Quote}}\) @XioGonz \(\color{#0cbb34}{\text{End of Quote}}\) Good Job!

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