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What is the solution to the linear equation? 6k + 10.5 = 3k + 12 k = 0.5 k = 2 k = 7.3 k = 9
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\(6k+10.5=3k+12\) The first thing we do is subtract 3k from both sides which should give us \(3k=1.5\) because \(3k+10.5−10.5=12−10.5\) and 12-10.5=1.5 so we get \(3k=1.5\) then we ÷3 to both sides of the equation \(\LARGE\frac{3k}{3}=\frac{1.5}{3}\) \(\cancel{\frac{3k}{3}}=\frac{1.5}{3}\) (3k/3 cancels) all that is left is \(\frac{1.5}{3}\) so \(\frac{1.5}{3}=?\) k=?
k=5
Not quite-
\(1.5÷3=?\)
o wait
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forgot to put the decimal
Yeah
0.5
Yes
k=0.5
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thank you
Yes your answer is A
np
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