Question

If sin y° = s over 8 and tan y° = s over t, what is the value of sec y°?

sec y° = 8s
sec y° = 8t
sec y° = 8 over t
sec y° = t over 8

Answer 1

\[\sin(y)=s/8\]
\[\tan(y)=s/t\]
\[\sec(y)=1/\cos(y)\]

Answer 2

from here. we want to find sec(y), lets find cos(y)
if \[\tan(y)=\sin(y)/\cos(y)\]
\[(s/t)=(s/8)/???\]
where ??? = cos(y)
we solve for ???

Answer 3

using some algebra, we can rearrage to solve for ???
\[??? = (s/8)/(s/t)\]
can u simplify this?

Answer 4

the right side of the eqn

Answer 5

Does it simplify to t/8?

Answer 6

correct
so \[\cos(y)=t/8\]
and \[\sec(y)=1/\cos(y)\]
so what is sec(y)

Answer 7

\[1/(t/8)\]

Answer 8

Oh to 8/t

Answer 9

correct have a good day, be sure to click best response if u wanna (up to u). :)

Answer 10

Thank you very much, I really hope I dont fail. And theres a part 2, I'm not religous but god help me.

Answer 11

Have a great day yourself.

Answer 12

np, and ty!

Answer 13

Hey I only got 3 wrong I'm pretty happy with that.