Ask
your own question, for FREE!
Ask question now!
Mathematics
9 Online
Seafoam:
An observer (O) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of elevation from his line of sight. How high is the kite flying over the building? You must show all work and calculations to receive full credit.
5 years ago
Join the QuestionCove community and study together with friends!
Sign Up
Seafoam:
@snowflake0531
5 years ago
snowflake0531:
heylo
5 years ago
Seafoam:
5 years ago
snowflake0531:
here, we have the opposite side and adjacent side, do you know whcih of the trigonometric equations we can use for this?
5 years ago
Seafoam:
Tangent
5 years ago
Join the QuestionCove community and study together with friends!
Sign Up
snowflake0531:
rightttttttt
so how would you set of the equationn
5 years ago
snowflake0531:
tan(theta)=opposite/adjacent
5 years ago
Seafoam:
tan(29)=h / 400
5 years ago
Seafoam:
Maybe?
5 years ago
snowflake0531:
yeppiiiiiiiiiiii
5 years ago
Join the QuestionCove community and study together with friends!
Sign Up
Seafoam:
yaayy
5 years ago
snowflake0531:
so then just put it into a calculator :)
400 (tan29)
5 years ago
Seafoam:
Ohh okk
5 years ago
Seafoam:
Ok so it went like 400 (tan(29)) is that it?
5 years ago
snowflake0531:
yepppppp
5 years ago
Join the QuestionCove community and study together with friends!
Sign Up
Seafoam:
So 221.72
5 years ago
Seafoam:
In feet
5 years ago
snowflake0531:
yes :)
5 years ago
Seafoam:
Yaay thank you so much!
5 years ago
snowflake0531:
:))
5 years ago
Join the QuestionCove community and study together with friends!
Sign Up
Seafoam:
I finally submitted this, its been open for days
5 years ago
snowflake0531:
that's nice
5 years ago
Seafoam:
Now on to suffering with the rest of my assignments, have a great day!
5 years ago
snowflake0531:
ha, me too, i need to do my ela, bye!
5 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question