Question

Solve the following system.

y = -2x 2 + 3x - 1 and x + y = -1.

The solutions are
and

Answer 1

rewrite them in this way and take them equal

y = -2x^2 +3x -1
y = -1 -x

-2x^2 +3x -1 = -1 -x

solve this quadratic for x
then using these x_1,2 you can calcule easy the y values

hope helped understandably easy

Answer 2

2,0

Answer 3

-2x^2 +3x -1 = -1 -x add to both sides 1 and get

-2x^2 +3x = -x add to both sides x and get

-2x^2 +4x = 0 factorize out the -2x and get

-2x(x -2) = 0

-2x = 0

x_1 = 0

x-2=0

x_2 = 2

and the y_1,2 values ?

Answer 4

x+y = -1

use this equation to calcule y_1,2 = ?

Answer 5

@AZ