help
with?
the second one is the diagram I have to use
so they gave you some sides \(\dfrac{PR}{AC} = \dfrac{x}{CB}\)
Let's reorient our triangles, okay?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Let's reorient our triangles, okay? \(\color{#0cbb34}{\text{End of Quote}}\) I don't know what that means but ok
|dw:1614865917252:dw|
I think you have to explain it better to her
What I mean is- let's just turn the triangle around so that way it faces the same direction as the bigger triangle
ok
I get that
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ so they gave you some sides \(\dfrac{PR}{AC} = \dfrac{x}{CB}\) \(\color{#0cbb34}{\text{End of Quote}}\)
so divide
no, first we have figure out what side we use for x
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ no, first we have figure out what side we use for x \(\color{#0cbb34}{\text{End of Quote}}\) and how do we do that subtract
take a look at this image
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ take a look at this image \(\color{#0cbb34}{\text{End of Quote}}\) I'm dumb I don't get it
do you see how the sides are in a proportion?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ do you see how the sides are in a proportion? \(\color{#0cbb34}{\text{End of Quote}}\) yes
so similarly for your triangle, I drew the triangles so you could see that they look so similar
so the AC side is in a ratio with the PR side of the other triangle similarly, the CB side would be in a ratio with the ____ what side? of the other triangle
ab
no no, it has to be the other triangle
and look at where CB is It's at the bottom, it's the base
what's the bottom/base of the other triangle?
rq
There you go!!
so that's our missing side in our equation
give me a min so I can log into class LOL
is rq .5 IDK I'm stupid
no
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ no \(\color{#0cbb34}{\text{End of Quote}}\) IDK then
so do they want you to find the value of RQ as well? or is RQ enough
I don't get it
I think RQ is your final answer
I don't think we have to find out what RQ is
I got pr
@az am I right
no no look at the image again
pq
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Yes, now you got it!
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilcutie2 pq \(\color{#0cbb34}{\text{End of Quote}}\) That's correct
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