Ask your own question, for FREE!
Mathematics 17 Online
lilcutie2:

help

jesternmais:

with?

lilcutie2:

the second one is the diagram I have to use

AZ:

so they gave you some sides \(\dfrac{PR}{AC} = \dfrac{x}{CB}\)

AZ:

Let's reorient our triangles, okay?

lilcutie2:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ Let's reorient our triangles, okay? \(\color{#0cbb34}{\text{End of Quote}}\) I don't know what that means but ok

AZ:

|dw:1614865917252:dw|

jesternmais:

I think you have to explain it better to her

AZ:

What I mean is- let's just turn the triangle around so that way it faces the same direction as the bigger triangle

lilcutie2:

ok

lilcutie2:

I get that

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ so they gave you some sides \(\dfrac{PR}{AC} = \dfrac{x}{CB}\) \(\color{#0cbb34}{\text{End of Quote}}\)

lilcutie2:

so divide

AZ:

no, first we have figure out what side we use for x

lilcutie2:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ no, first we have figure out what side we use for x \(\color{#0cbb34}{\text{End of Quote}}\) and how do we do that subtract

AZ:

take a look at this image

1 attachment
lilcutie2:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ take a look at this image \(\color{#0cbb34}{\text{End of Quote}}\) I'm dumb I don't get it

AZ:

do you see how the sides are in a proportion?

lilcutie2:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ do you see how the sides are in a proportion? \(\color{#0cbb34}{\text{End of Quote}}\) yes

AZ:

so similarly for your triangle, I drew the triangles so you could see that they look so similar

AZ:

so the AC side is in a ratio with the PR side of the other triangle similarly, the CB side would be in a ratio with the ____ what side? of the other triangle

lilcutie2:

ab

AZ:

no no, it has to be the other triangle

AZ:

and look at where CB is It's at the bottom, it's the base

AZ:

what's the bottom/base of the other triangle?

lilcutie2:

rq

AZ:

There you go!!

AZ:

so that's our missing side in our equation

AZ:

give me a min so I can log into class LOL

lilcutie2:

is rq .5 IDK I'm stupid

AZ:

no

lilcutie2:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ no \(\color{#0cbb34}{\text{End of Quote}}\) IDK then

AZ:

so do they want you to find the value of RQ as well? or is RQ enough

lilcutie2:

I don't get it

AZ:

I think RQ is your final answer

AZ:

I don't think we have to find out what RQ is

lilcutie2:

I got pr

lilcutie2:

@az am I right

AZ:

no no look at the image again

lilcutie2:

pq

AZ:

|dw:1614867169888:dw|

AZ:

Yes, now you got it!

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @lilcutie2 pq \(\color{#0cbb34}{\text{End of Quote}}\) That's correct

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!