Who can help with inequality?
post it
−8x + 40 > −16
hmmm, first, let's ignore the > for just hte first step -8x + 40 = -16 subtract 40 from eachside
-24
um, subtact 40 what is 16 plus 40?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lorena123 -24 \(\color{#0cbb34}{\text{End of Quote}}\) No bc when you subtract a negative and a negative your technically add then putting the negative sign back beside it
answer is 3 but the sign is the problem
no
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lorena123 answer is 3 but the sign is the problem \(\color{#0cbb34}{\text{End of Quote}}\) Wrong
one of these is the answer H. x > −3 J. x < −3
−8x + 40 > −16 -8x > -56 8x < 56 x < what
x < −3
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lorena123 x < −3 \(\color{#0cbb34}{\text{End of Quote}}\) No, incorrect.
bruh, don't be so stubborn with teh negative3 3 lol
im confused lol
\(\color{#0cbb34}{\text{Originally Posted by}}\) @snowflake0531 −8x + 40 > −16 -8x > -56 8x < 56 x < what \(\color{#0cbb34}{\text{End of Quote}}\) do you get how i got -8x > -56
no
do you know how to solve x+4=10 what is x
i supposebly did work on the sheet but its probably wrong
How about we do it step by step? the first step is to subtract 40 from both sides Change the plus in `+40` to a minus \(−8x\cancel{+40}>−16\) \(~~~~~~~\cancel{-40}~~~~-40\) What is (-16)-40=?
i got -24 but idk are we adding or subtracting
subtracting
you did 40-16 you should do 40+16 and then add a negative sign
dont mind the messy handwriting
40 plus 16 is 56 so then -56
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lorena123 40 plus 16 is 56 so then -56 \(\color{#0cbb34}{\text{End of Quote}}\) yes
ok wait but im stuck at do we add or sub?
Yes so now we have \(−8x>−56\) so ÷-8 to both sides of the equation do you think you can do that?
yes i can
Ok, lmk what you get-
7.25
Close but no,
round it to 7
not rounding 56/8 is 7
Is this the answer x < 7
\(\color{#0cbb34}{\text{Originally Posted by}}\) @lorena123 Is this the answer x < 7 \(\color{#0cbb34}{\text{End of Quote}}\) yes
ok thx
np :) thanx for the medal
Np
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