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Please help me You have 42 coins valued at $3.00. Some of the coins are dimes and some are quarters. Find the number of each you have.
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@AZ plz help
How do you think we find the number of each u have?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @baddie15 @AZ plz help \(\color{#0cbb34}{\text{End of Quote}}\) u there?
let's let d = # of dimes and q = # of quarters since there are 42 coins ---> d + q = 42 the monetary value of (d) dimes is 0.10d, similarly for quarters it's 0.25q since the total value is $3.00 ---> 0.10d + 0.25q = 3 making this your system: d + q = 42 0.10d + 0.25q = 3 solve via substitution or elimination
she wants a direct answer so lets move on
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