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Which of the following is the factored form of the given equation? 6x^2 + 2x - 8 = 0 2(3 x + 4)( x + 1) = 0 (6 x + 1)( x - 8) = 0 2(3 x + 4)( x - 1) = 0
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Have you tried it?
five times i did
and what you got ?
wrong
could you share your approach? It'd be better here, so that I can rectify it.
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x2 - 8x + 3 =0 x2 - 8x + 16 = -3 - 16 (x - 4)(x - 4) = -19 (x - 4)^2 = -19
that's a different question
6x^2+2x-8=0 2(3x^2+x-4)=0 2(3x^2+3x-2x-4)=0 I think non of these answer
6x^2 + 2x - 4 = 0 8 replace by 4 then solve your question
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